(Q33)Rahim removes all the hearts from the cards. What is the probability of

(i) Picking out an ace from the remaining pack.

(ii). Picking out a diamond.

(iii). Picking out a card that is not a heart

(iv)Picking out the Ace of hearts.

Answer :

Total number of cards in the deck = .

Total number of hearts in the deck of cards =13.

When Hearts are removed, remaining cards = 52 - 13 = .

(i) Picking out an Ace:

Number of outcomes favourable to Ace = 3 [∵ ♦ A, ♥ A, ♠ A, ♣ A]

Total number of possible outcomes from the remaining cards = (after removing Hearts.)

Probability = P(A) =
No. of favourable outcomes
Total no. of outcomes
=
3
=
1

(ii) Picking out a diamond:

Number of favourable outcomes to diamonds (♦) = 13

Total number of possible outcomes =

∴ p(♦) =
13
=
1

(iii) Picking out a card that is 'not a heart':

As all hearts are removed, the remaining cards are all non-heart cards. So the picked card will be definitely a non-heart card. So this is a sure event.

Hence its probability is one

P(E) =
=

(iv) Picking out the Ace of Hearts:

a) As all the heart cards are removed the left over cards will have three suits (i) spades, (ii), clubs, (iii) diamonds of each 13.

Hence total outcomes = × 13 = But among them there is no Ace of heart. So number of favourable outcomes for picking Ace of heart = .

∴ Probability P(E) =
=

So it is an impossible event.

b) If picking from the rest of the cards, it is an impossible event and hence probability is .